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.11 moles of water vapor contains how many liters?

1 Answer

3 votes

Answer:

2.46 L

Step-by-step explanation:

At standard temperature and pressure 1 mole of any ideal gas occupies 22.4 L of volume.

SO, at STP,

Volume = Mole × 22.4 L/mol

Volume = 0.11 mol × 22.4 L/mol

Volume = 2.46 L

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