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Explain how complex fractions can be used to solve problems involving ratios

User IConfused
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so when you have ratios, some are unknowns you have to create complex fractions from them. Bring to the same donominator, and solve for x.

Ex: we have this portion:
2 -x
5-45

and we change it into fractions

2/5 =x/25

2x9/5x9 = x/45

answer would be 18=x

in case of more complex fractions it may become in handy.

Your welcome!!
User Chanom First
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