Question

There were 60 cows and chickens on Ted's farm. One afternoon Tedcounted 156 legs in all. How many cows and chicken are there?

Answer 1

`\begin{gathered} w=Number\text{ of cows} \\ c=\text{ Number of chickens} \\ \text{There were 60 cow and chickens} \\ \text{hence} \\ w+c=60 \\ Cows\text{ have 4 legs and chickens have 2 legs, so} \\ 4w+2c=156 \\ \text{The system equation is} \\ w+c=60\text{ (1)} \\ 4w+2c=156\text{ (2)} \\ Solv\text{ing from (1) w} \\ w=60-c \\ U\sin g\text{ w in (2)} \\ 4w+2c=156 \\ 4(60-c)+2c=156 \\ 240-4c+2c=156 \\ -4c+2c=156-240 \\ -2c=-84 \\ c=(-84)/(-2) \\ c=42 \\ \text{And} \\ w=60-c \\ w=60-42 \\ w=18 \\ \text{Therefore the number of cows is 18 and }the\text{ number of chickens is 42} \end{gathered}`

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