Question

Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x2 + 3x – 8?

Answer 1

For this case we have the following quadratic function:

`0 = 2x^2 + 3x - 8`
Using the method of the resolver we have:

`x = (-b +/- √(b^2-4ac) )/(2a)`
Substituting values:

`x = (-3 +/- √(3^2-4(2)(-8)) )/(2(2))`
Rewriting we have:

`x = (-3 +/- √(9+64) )/(4)`

`x = (-3 +/- √(73) )/(4)`
Doing the calculations we have the results are:

`x1 = 1,386 x2 = -2,886`
Rounding the positive solution to the hundredth hundredth:

`x1 = 1.39`
Answer:
The positive solution to the quadratic equation is:

`x = 1.39`

Answer 2

A quadratic equation has the general formula expressed as:

ax^2 + bx - c = 0

This equation can be solved by the quadratic formula which is expressed as:

x = ( -b (+ or -) √(b^2 - 4ac) / 2a

From the given equation,

a = 2
b = 3
c = -8

x = ( -3 (+ or -) √(3^2 - 4(2)(-8)) / 2(2)
x1 = 1.386
x2 = -2.886