Question

An object with a mass of 22.22 kg rests on a plane inclined 1.35° from horizontal. What is the coefficient of static friction on the incline?

Answer 1

Given data

*The given mass of the object is m = 22.22 kg

*The angle above the horizontal is

`\theta=1.35^0`

The formula for the coefficient of static friction on the incline is given as

`\mu_s=\tan \theta`

Substitute the values in the above expression as

`\begin{gathered} \mu_s=\tan (1.35^0) \\ =0.02 \end{gathered}`