Question

A plane takes off at an angle of elevation of 15° and travels in a straight line for 3,000 meters. What is the height of the plane above the ground at this instant?

Answer 1

Answer:776

Explanation:

Answer 2

Forming thw diagram, you have the length of the hypotenuse, and you want to find the height, which is the 'opposite length to the angle'

So using SOHCAHTOA we have:
sin15 = height / 3000
height = 3000 sin 15 height = 776.46m

So, the height of the plane above the ground at this instant is 776.46m