3.3k views
3 votes
What is the additive inverse of the complex number 9 – 4i?. . A.–9 – 4i. B.–9 + 4i. C.9 – 4i. D.9 + 4i

User Blackdad
by
7.8k points

2 Answers

4 votes

Answer:

b. –9 + 4i

Explanation:

User Duvan
by
8.3k points
2 votes
Given the complex number 9 - 4i, the additive inverse is the number that when added to the original number, would equate to zero. Another term this may be known as is the additive identity. The additive inverse is simply:
(a + bi) = -(a + bi)

Given: 9 - 4i

-(9 - 4i) = -9 + 4i

Therefore, the answer is B.
User GeraltDieSocke
by
7.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories