Question

What mass of oxygen is needed for the complete combustion of 4.60×10−3g of methane?

Answer 1

First step in answering the question is to establish a balanced chemical reaction equation. More specifically, a combustion chemical equation.

CH4 + 2O2 ---> CO2 + 2H20

Then using dimension analysis:


`4.60*10^(-3) g CH4 ( (moleCH4)/(16 g CH4)) * ( (2mole O2)/(mole CH4)) * ( (32 g O2)/(mole O2) ) = 0.0184 g O_(2)`