Question

When 1.82 moles of HCL reacts with excess MnO2, how many moles of Cl2 form

Answer 1

Answer: 0.455 moles of chlorine gas is formed.

Step-by-step explanation:

We are given:

Moles of HCl = 1.82 moles

The chemical equation for the reaction of
`MnO_2` and HCl follows:

`MnO_2(s)+4HCl(aq.)\rightarrow Cl_2(g)+MnCl_2(aq.)+2H_2O(l)`

By Stoichiometry of the reaction:

If 4 moles of HCl produces 1 mole of chlorine gas

So, 1.82 moles of HCl will produce =
`(1)/(4)* 1.82=0.455mol` of chlorine gas

Hence, 0.455 moles of chlorine gas is formed.