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What is f(x)/g(x) when f(x)=-2x^3+x^2+16x-15 and g(x)=x+3?

1 Answer

4 votes
Hello,


if x≠-3


f(-3)=-2(-3)^3+(-3)²+16(-3)-15=-2*(-27)+9-48-15=54+9-48-15=0

f(x)/g(x)=(-2x^3+x²+16x-15)/(x+3)=(x+3)*(-2x²+7x-5)/(x+3)= -2x²+7x-5


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