Assuming it is complete combustion, the products would be CO2 and H2O.
We must have a balanced equation,
C6H6 + (15/2)O2 -> 6CO2 + 3H2O
This means 1 mol C6H6 yields 6 mol CO2
5.45 mol C6H6 ( 6 mol CO2 / 1 mol C6H6) = 32.7 mol CO2
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