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The axis of symmetry for the graph of the function f(x)=3x^2+bx+4 is x=3/2. what is the value of b
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The axis of symmetry for the graph of the function f(x)=3x^2+bx+4 is x=3/2. what is the value of b

User Fanie
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2 Answers

2 votes

Answer:-9

Explanation:

got 100 on test :)

User Lost Left Stack
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4 votes
Since the axis of symmetry is the vertical line through the vertex, the line is given by
x=-B/(2A) = -B/(2*3) = 3/2
solving B
B=(3/2)*(-2*3)=-9

User Jackkobec
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8.6k points
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