What is the product? (6r − 1)(−8r − 3) −48r2 − 10r + 3 −48r2 − 10r − 3 −48r2 + 3 −48r2 − 3

asked Jul 19, 2017 216k views

5 votes

What is the product?

(6r − 1)(−8r − 3)

−48r2 − 10r + 3
−48r2 − 10r − 3
−48r2 + 3
−48r2 − 3

by Norda

9.7k points

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2 votes

$(6r-1)(-8r-3)=6r(-8r-3)-1(-8r-3) \\ =-48 r^(2) -18r+8r+3 \\ =-48 r^(2) -10r+3$

Toby Speight answered Jul 24, 2017

7.9k points

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