Question

If sin Θ = 5 over 6 , what are the values of cos Θ and tan Θ? (2 points)

cos Θ = ± 11 over 36 ; tan Θ = ± 1 over 11
cos Θ = ± square root 11 over 6 ; tan Θ = negative 1 over 11
cos Θ = ± 11 over 6 ; tan Θ = 11 over 6
cos Θ = ± square root 11 over 6 ; tan Θ = ± 5 square root 11 over 11

Answer 1

cosΘ=±
`(√(11) )/(6)`

tanΘ =±
`(5√(11) )/(11)`

Explanation:

I took the test and got it right

Answer 2

cos² (theta) = 1 - (5/6)²
cos² (theta) = 1 - 25/36 = 11/36
cos(theta) =
`\sqrt{ (11)/(36) }=\pm ( √(11) )/(6)`
tan(theta) = sin(theta) / cos (theta)=
`\pm(5/6)/( √(11)/6 )= \pm (5)/( √(11) ) =\pm (5 √(11) )/(11)`
Answer: D)