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If sin Θ = 5 over 6 , what are the values of cos Θ and tan Θ? (2 points)

cos Θ = ± 11 over 36 ; tan Θ = ± 1 over 11
cos Θ = ± square root 11 over 6 ; tan Θ = negative 1 over 11
cos Θ = ± 11 over 6 ; tan Θ = 11 over 6
cos Θ = ± square root 11 over 6 ; tan Θ = ± 5 square root 11 over 11

User Betaorbust
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2 Answers

7 votes

Answer:

cosΘ=±
(√(11) )/(6)

tanΘ =±
(5√(11) )/(11)

Explanation:

I took the test and got it right

User Ivan Shumilin
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7.7k points
4 votes
cos² (theta) = 1 - (5/6)²
cos² (theta) = 1 - 25/36 = 11/36
cos(theta) =
\sqrt{ (11)/(36) }=\pm ( √(11) )/(6)
tan(theta) = sin(theta) / cos (theta)=
\pm(5/6)/( √(11)/6 )= \pm (5)/( √(11) ) =\pm (5 √(11) )/(11)
Answer: D)
User Bugfixer
by
7.3k points

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