Question

(08.01)

Identify the 31st term of an arithmetic sequence where a1 = 26 and a22 = −226. (2 points)


−334
−274
−284
−346
Score: 2 of 2

Answer 1

Here is your answer:

In order to find the answer to this question you will have too:

1. Identify first the common difference of the arithmetic sequence....

2. Solve for the term.....

3. Then you will have your answer!

`(d=(a^(22) - a^1))/(22-1)`

`(d=(-226-26))/(22-1=-12)`

`a^(31) = a^1 + (n - 1)d`

`a^(31) = 26 + (31 - 1)(-12)`

`a^(31) = -334`

Which would mean your answer is option A "-334."

Hope this helps!

Nonportrit

Answer 2

Identify first the common difference of the arithmetic sequence by the following,

d = (a22 - a1) / 22 - 1

d = (-226 - 26) / 22 -1 = -12

Solving for the 31st term,

a31 = a1 + (n - 1)d

a 31 = 26 + (31 - 1)(-12)

a 31 = -334

Therefore, the answer is letter A. -334.