Question

What is the range of the function f(x) = 3x2 + 6x – 8?

y ≥ –1

y ≤ –1

y

y

Answer 1

c

Explanation:

Answer 2

f(x) is a quadratic equation with the x-side squared and a is positive which means that the graph of the function is a parabola facing up. The range of f(x) is given by y, where k is the y-coordinate of the vertex.

`f(x)=3 x^(2) +6x-8`, written in vertex form is

`y=3 (x+1)^(2) -11`, where (h, k) = (-1, -11)
Therefore, range =y ≥ -11