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What are the domain, range, and asymptote of h(x) = 2x + 4? domain: x > 0; range: y ; asymptote: y = 0 domain: x ; range: y ; asymptote: y = –4 domain: x is a real number; range: y > 0; asymptote: y = 0 domain: x ; range: y > 0; asymptote: y = –4

2 Answers

2 votes

Consider the function
y=2^(x+4). First, note that parent function
y=2^x has

  • the domain
    x\in (-\infty,\infty) (all real numbers);
  • the range
    y>0 (all positive real numbers);
  • the asymptote
    y=0 (horizontal line).

The graph of the function
y=2^(x+4) can be obtained from the parent function using translation 4 units to the left. This translation doesn't change the domain, the range and the asymptote of the parent function.

Answer: correct choice is C

User Nash Worth
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7.6k points
3 votes

Answer:

Option 3 is correct.


D=(-\infty,\infty)[x|x\in {R}]


R=(0,\infty)[y|y>0]

y=0 is the asymptote.

Explanation:

Given : The function
h(x) = 2^(x + 4)

To find : The domain, range, and asymptote of the given function.

Solution :

The given function
h(x) = 2^(x + 4) is an exponential function.

Domain is where the function is defined.

Therefore,
D=(-\infty,\infty)[x|x\in {R}]

The range is the set of values that correspond with the domain.

At x tends to
-\infty function tends to zero.

At x tends to
\infty function tends to
\infty

Therefore,
R=(0,\infty)[y|y>0]

Exponential functions have a horizontal asymptote.

The equation of the horizontal asymptote is y=0.

Therefore, Option 3 is correct.

User Chris Peters
by
7.1k points