Question

The diagonal of a TV is 26 inches long. Assuming that this diagonal forms a pair of 30-60-90 right triangles, what are the exact length and width of the TV?

Answer 1

Hello,
let's assume a the width, b the heigth.

sin 30°=a/26=1/2==>a=26/2=13 (in)
cos 30°=b/26=√3/2==>b=26*√3 / 2=13√3≈22.51666.... (in)