Question

An upward force is applied to a 6.0–kilogram box. this force displaces the box upward by 10.00 meters. what is the work done by the force on the box?

Answer 1

work = fs = mgh [Ep] = 6(10)(10) = 100

Answer 2

The work done by the force on the box is W = 588 J

Step-by-step explanation:

The work done by the force on the box can be expressed as:

`W=mg(h_(2)-h_(1))`

where m is the mass of the box, g is the gravitational force g=
`g=9.8(m)/(s^(2))` and
`h_(2)`,
`h_(1)` are the heights of the box in at final and initial moment.

Replacing the values, you have:

`W=6.0kg*9.8(m)/(s^(2))*(10.00m-0.00m)`

`W=588(kgm^(2))/(s^(2))`

that is W = 588 J