Question

A tow truck exerts a net horizontal force of 1050 n on a 760-kg car. what is the acceleration of the car during this time?

Answer 1

a = f/m

a= 1050/760

a= 1.38m/s^2

Answer 2

Answer: The acceleration of the car during this time is 1.38
`m/s^2`.

Step-by-step explanation:

Force exerted on the two truck = 1050 N

Mass of the car = 760 kg

According to Newton's second law of Motion;

`Force=Mass * Acceleration`

`1050 N=760 kg* Acceleration`

`Acceleration=(1050 N)/(760 kg)=1.38 m/s^2`

The acceleration of the car during this time is 1.38
`m/s^2`.