Question

Ethylene glycol (antifreeze) has a density of 1.11 g/cm3. what is the volume in liters of 3.46 kg of ethylene glycol?

Answer 1

To find the volume of 3.46 kg of ethylene glycol, divide the mass by the density. The volume is 3.11712 L.

Step-by-step explanation:

To find the volume of 3.46 kg of ethylene glycol, you can use the formula:

Volume = Mass / Density

First, convert the mass of ethylene glycol from kilograms to grams by multiplying by 1000 (since there are 1000 grams in a kilogram): 3.46 kg * 1000 g/kg = 3460 g

Then, use the given density of ethylene glycol (1.11 g/cm³) to find the volume: Volume = 3460 g / 1.11 g/cm³ = 3117.12 cm³

Finally, convert the volume from cubic centimeters to liters by dividing by 1000 (since there are 1000 cm³ in a liter): 3117.12 cm³ / 1000 = 3.11712 L

Answer 2

Density is a physical property which describes the mass of a substance per unit of volume of the substance. It is expressed as Density = m / V and it has units like g/cm^3. We use the density given to solve the problem.

3.46x10³ g / 1.11 g/cm³ = 3117.12 cm³ (1 L / 1000 cm³) =3.12 L