Question

If an object of 0.550 kg is lifted from the floor to a height of 3.50m, how much work is done by the lifting force, what is the kinetic energy, and what is the velocity?

Answer 1

`Work=(Force)/(distance)\\\\Force=mass*gravity\\Force=0,550*9,8=5,39N\\ distance=3,5m\\\\ Work=(5,39N)/(3,5m)=1,54J\\\\ Kinetic\ energy=Work=1,54J\\\\ Kinetic \ energy=(1)/(2)mv^2\ \ \ |*2\\ 2Kinetic \ energy=mv^2\\\ \sqrt{(2Kinetic \ energy)/(m)}=v\\\\ velocity=\sqrt{(2*1,54)/(0,55)}=\sqrt{(3,08)/(0,55)}=√(5,6)=2,37(m)/(s)`