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Find all polar coordinates of point P = (6, 31°).

User Goli
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2 Answers

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(6,(31pi/180)+2 n pi) (-6,(31pi/180)+2 n pi)
User Jiks
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6 votes

Answer:

All polar coordinates of point P = (6, 31°) are
P=(6,(31\pi)/(180)+2n\pi) and
P=(-6,(31\pi)/(180)+(2n+1)\pi) where, n is an integer.

Explanation:

The given polar coordinates of a point are


P=(6,31^(\circ))

If a point is defined as


P=(r,\theta)

Where, θ is in radian, then the polar coordinates of that points are


(r,\theta)=(r,\theta+2n\pi)


(r,\theta)=(-r,\theta+(2n+1)\pi)

Where, n is an integer.

The given point in radian form is


P=(6,31* (\pi)/(180))


P=(6,(31\pi)/(180))

All polar coordinates of point P = (6, 31°) are


P=(6,(31\pi)/(180)+2n\pi)


P=(-6,(31\pi)/(180)+(2n+1)\pi)

Where, n is an integer.

User Isabela
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