2 Answers

Isabela · Answer 1 · 2017-01-23T06:43:53+0000

Answer:

All polar coordinates of point P = (6, 31°) are
$P=(6,(31\pi)/(180)+2n\pi)$ and
$P=(-6,(31\pi)/(180)+(2n+1)\pi)$ where, n is an integer.

Explanation:

The given polar coordinates of a point are

$P=(6,31^(\circ))$

If a point is defined as

$P=(r,\theta)$

Where, θ is in radian, then the polar coordinates of that points are

$(r,\theta)=(r,\theta+2n\pi)$

$(r,\theta)=(-r,\theta+(2n+1)\pi)$

Where, n is an integer.

The given point in radian form is

$P=(6,31* (\pi)/(180))$

$P=(6,(31\pi)/(180))$

All polar coordinates of point P = (6, 31°) are

$P=(6,(31\pi)/(180)+2n\pi)$

$P=(-6,(31\pi)/(180)+(2n+1)\pi)$

Where, n is an integer.

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