Question

The vertex of the graph of y=(x-1)^2-5 is

Answer 1

(1,-5)

Explanation:

Answer 2

for y = (x-h)^2 + k
the vertex is h,k

comparing
y=(x-1)^2-5 with y = (x-h)^2 + k

we have h = 1, k = -5

so the vertex of y=(x-1)^2-5 is (1,-5)