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Find the value of Q in the system so that the solution to the system is x-3y=4 2x+Qy=8
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Find the value of Q in the system so that the solution to the system is

x-3y=4
2x+Qy=8

User Mwalling
by
7.8k points

1 Answer

5 votes
x -3y = 4 multiplie both sides by -2 => -2x +6y = -8
2x +Qy = 8

-2x +6y = -8
2x +Qy = 8
------------------ assume the same terms
0 6y +Qy = 0

6y +Qy = 0

Qy = -6y divide both sides by y and will get

Q = -6
User Wolfgang Stengel
by
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