Question

Vertex of the parabola whose equation is y = x2 6x 2.

Answer 1

(-3,-7)

Explanation:

i checked the other persons work and it is right.

Answer 2

Complete the square to put equation
`y = x^(2) + 6x + 2` to the form
`a ( x + h )^(2) + k`


`x^(2) + 6x = -2`
(half the 6 then square it to find the third term and make the LHS into a
perfect square. add the number to both sides
`( (6)/(2) )^(2)`)


`x^(2) + 6x + 9 = -2 + 9`
(factorise the LHS and simplify the RHS)


`( x + 3 )^(2) = 7`


`( x + 3 )^(2) - 7 = 0`

In this form, we know that the vertex is (-h , k )
∴ the vertex of this equation is (-(3) , -7 )