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A 1.0 m h2s solution has a ph = 3.75 at equilibrium. what is the value of ka?

User Madmadi
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2 Answers

5 votes

Answer:

3.16 × 10−8

Step-by-step explanation:

A 1.0 m h2s solution has a ph = 3.75 at equilibrium. what is the value of ka?-example-1
User BarelyFitz
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When H2S dissociates in water, it forms 2H+ and S2-. This means the expression of Ka [H+]^2[S2-] / [H2S]. H+ concentration can be derived from the pH thru 10^-pH. This is equal to 1.7783 x10^-4 M. Ka now becomes [1.7783 x10^-4 M]^2*[1.7783 x10^-4 M/2]/ [1.0-1.7783 x10^-4 M] equal to 2.8122 x10^-12.
User Persepolis
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