Question

Solve 4sin^2 x-3=0 find two values of sinx that satisfy this equation

Answer 1

`4 sin^(2) x-3=0 \\ 4 sin^(2) x=3 \\ sin^(2) x= (3)/(4) \\ sinx= \pm \sqrt{ (3)/(4) } \\ sinx= ( √(3) )/(2) \ or \ sinx=- ( √(3) )/(2) \\ x= ( \pi )/(3) , \ (2 \pi )/(3) , \ (4 \pi )/(3) , \ (5 \pi )/(3)`