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Line segment AB has a length of 4 units. It is translated 2 units to the right on a coordinate plane to obtain line segment A'B'. What is the length of A'B'?

User Novakov
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length of the line segment does not change. you are just moving it 2 units to the right. answer would be 4 units
User Norcalli
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Answer: The length of A'B' is 4 units.

Step-by-step explanation: Given that the line segment AB has a length of 4 units and it is translated 2 units to the right on a coordinate plane to obtain line segment A'B'.

We are to find the length of A'B'.

According to the given information, the line segment AB is translated 2 units to the right.

So, the point A and B, both will be translated two units to the right.

Let us consider the co-ordinates of the endpoints of AB are (1, 2) and (5, 2), so that the length of AB (using distance formula) is


AB=√((5-1)^2+(2-2)^2)=√(16)=4~\textup{units}.

After translating 2 units right, the point A will translate to A'(3, 2) and B will translate to B'(7, 2).

Therefore, the length of A'B' will be


A'B'=√((7-3)^2+(2-2)^2)=√(16)=4~\textup{units}.

Thus, the length of A'B' is 4 units.

Line segment AB has a length of 4 units. It is translated 2 units to the right on-example-1
User Tommi Kyntola
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