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A series circuit contains a 9-volt battery, a 3-ohm resistor and a 2-ohm resistor. What is the voltage drop across the 2-ohm resistor?

3.2 V
3.4 V
3.6 V
3.8 V

User Bueno
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8.0k points

2 Answers

4 votes

Answer:

3.6V

Step-by-step explanation:

User Ojus Sangoi
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5 votes
Since everything in the circuit is in series .. .

-- The total resistance is (3 + 2) = 5 ohms.

-- The voltage across the 3-ohm resistor is 3/5 of the total voltage.

-- The voltage across the 2-ohm resistor is 2/5 of the total voltage.

(2/5) of (9 volts) = 18/5 = 3.6 volts .

User The Recruit
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7.5k points