Question

A sample of a compound contains 30.0 g C and 5.05 g H. Its molar mass is 78.12 g/mol. What is the compound’s molecular formula?

CH
C2H2
C6H6
C6H

Answer 1

Bruh the guy above is tweaking its C6H6

Step-by-step explanation:

Answer 2

The relative atomic mass of C is 12 g. So, to calculate how many atoms of C there are, we will divide 30 g by 12 g:
30 g ÷ 12 g = 2.5

The relative atomic mass of H is 1 g. So, to calculate how many atoms of C there are, we will divide 5.05 g by 1 g:
5.05 g ÷ 1 g = 5.05 ≈ 5

Now, let's calculate the ratio of C and H atoms:

`(H-atoms)/(C-atoms) = (5)/(2.5) =2`

This means there are 2 H atoms more than C atoms and therefore, the compound’s molecular formula is CH₂.