An = cos(npi/2). If convergent find limit of sequence?

Question

asked May 7, 2017 54.2k views

1 Answer

Kevin Hsiao · Answer 1 · 2017-05-12T16:01:33+0000

The sequence is: cos(π/2), cos (π ), cos (3π/2), cos ( 2π ),...
or: 0,-1,0,1,0,-1,0,1,... Since cos (nπ/2) oscillates between -1 and 1 as n tends to infinity, this sequence is divergent (limit does not exist).

An = cos(npi/2). If convergent find limit of sequence?

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

Related questions

Categories

Other Questions