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If f(x)=e^sinx, how many zeros does f'(x) have on the closed interval [0,2╥]?
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If f(x)=e^sinx, how many zeros does f'(x) have on the closed interval [0,2╥]?

User Mike Heinz
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f(x)=e^(sinx)
f´(x)=
e^(sinx) *cos x
f´(x)= 0 for cos x =0
f´(x) have two zeroes on the closed interval [ 0,2π].
x=π/2 and x=3π/2

User Lucky Yang
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