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Solve for x: |x − 2| + 10 = 12 x = 0 and x = 4 x = −4 and x = 0 x = −20 and x = 4 No Solution
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Solve for x: |x − 2| + 10 = 12 x = 0 and x = 4 x = −4 and x = 0 x = −20 and x = 4 No Solution
asked
Sep 9, 2017
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Solve for x: |x − 2| + 10 = 12
x = 0 and x = 4
x = −4 and x = 0
x = −20 and x = 4
No Solution
Mathematics
high-school
Makeda
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+ or - (x - 2) + 10 = 12
+ or - (x - 2) = 12 - 10 = 2
x - 2 = 2 or -(x - 2) = 2
x - 2 = 2 or -x + 2 = 2
x = 2 + 2 or x = 2 - 2
x = 4 or x = 0
i.e. first option.
KymikoLoco
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Sep 9, 2017
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KymikoLoco
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1. If x-2≥0, x≥2
x-2+10=12
x+8=12
x=12-8
x=4
2.If x-2≤0, x≤2
-(x-2)+10=12
-x+2+10= 12
x = 0
Answer: A) x=0 and x=4
Mobile Dan
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Sep 15, 2017
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Mobile Dan
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