Question

How many grams would 3.36 × 1023 molecules of copper (II) sulfate (CuSO4) weigh?

Answer 1

Molar mass ( CuSO₄) = 159.609 g/mol

159.609 g ----------------- 6.02 x 10²³ molecules
? g ------------------ 3.36 x 10²³ molecules

mass = ( 3.36 x10²³) x 159.609 / 6.02 x 10²³

mass = 5.36 x 10²⁴ / 6.02 x 10²³

mass = 8.90 g

hope this helps!

Answer 2

The mass of the given number molecules of copper sulfate 88.98 g.

Step-by-step explanation:

Number of copper sulfate molecules =
`3.36* 10^(23)`

Moles of copper sulfate : x

Number of molecules = Moles
`* N_A`

`3.36* 10^(23) =x* 6.022* 10^(23)`

x = 0.5579 moles

Mass of 0.5579 moles of copper sulfate:

`0.5579 mol* 159.5 g/mol=13.38 g`

The mass of the given number molecules of copper sulfate 88.98 g.