Answer : The atmospheric pressure of water if boiling at 81 °C will be 369 mmHg.
Explanation : The vapor pressure of boiling water can be calculated using the Antoine Equation:
log P = A -
,
where P is the pressure in mmHg,
A = 8.07131,
B = 1730.63
C = 233.426
and T = temperature in °C (81°C)
Substituting the given values, we get,
Log P = 8.07131−
![[(1730.63)/(233.426 + 81)]](https://img.qammunity.org/2017/formulas/chemistry/high-school/kzy7qd9qtic5j4qsqoe5423riejg7qsrub.png)
Therefore, Log P =8.07131 − 5.5041 = 2.567.
Now, P =
=369 mmHg.
Hence, the atmospheric pressure will be 369 mmHg.