We have to obtain 200.5 g of pure Cu. We have to convert that value into moles. To do that we will use the molar mass of Cu.
molar mass of Cu = 63.55 g/mol
moles of Cu = mass of Cu/molar mass of Cu
moles of Cu = 200.5 g/(63.55 g/mol)
moles of Cu = 3.155 moles
So we want to mine 200.5 g of pure Cu or 3.155 moles of Cu.
One molecule of the mineral chalcopyrite (CuFeS₂) contains one atom of Cu, one atom of Fe and 2 atoms of Fe. So, 1 mol of CuFeS₂ contains 1 mol of Cu atoms. Or, if we want to obtain 1 mol of Cu atoms we have to mine 1 mol of CuFeS₂. We will use that conversion to get the number of moles of CuFeS₂ that we have to mine to get 3.155 moles of pure Cu.
1 mol of CuFeS₂ = 1 mol of Cu
moles of CuFeS₂ = 3.155 moles of Cu * 1 mol of CuFeS₂/(1 mol of Cu)
moles of CuFeS₂ = 3.155 moles
If we want to get 3.155 moles of pure Cu, we have to mine 3.155 moles of CuFeS₂. Finally we can convert those moles into grams using the molar mass of CuFeS₂ and then convert it to kg.
atomic mass of Cu = 63.55 amu
atomic mass of Fe = 55.85 amu
atomic mass of S = 32.07 amu
molar mass of CuFeS₂ = 63.55 + 55.85 + 32.07 * 2
molar mass of CuFeS₂ = 183.54 g/mol
mass of CuFeS₂ = moles of CuFeS₂ * molar mass of CuFeS₂
mass of CuFeS₂ = 3.155 moles * 183.54 g/mol
mass of CuFeS₂ = 579 g
1000 g = 1 kg
mass of CuFeS₂ = 579 g = 579 g * 1 kg/(1000 g)
mass of CuFeS₂ = 0.579 kg
Answer: We have to mine 0.579 kg of chalcopyrite to obtain 200.5 g of pure Cu.