Question

The small piston of a hydraulic lift has a diameter of 8.0 cm, and its large piston has a diameter of 40cm. the lift raises a load of 15,000N.

a) Determine the force that must be applied to the small piston.
b) Determine the pressure applied to the fluid in the lift.

Answer 1

Part a)

F = 600 N

Part b)

P = 119366.20 Pascal

Step-by-step explanation:

Part a)

As we know that by Pascal's law pressure must be transmitted through out the liquid without any change

So pressure at bigger piston = pressure at smaller piston

`(F_1)/(A_1) = (F_2)/(A_2)`

`(F_1)/(\pi(0.04)^2) = (15000)/(\pi(0.20)^2)`

now by solving above equation we have

`F_1 = (16)/(400) (15000)`

`F_1 = 600 N`

Part b)

Pressure applied at fluid is given as

`P = (F)/(A)`

`P = (15000)/(\pi(0.20)^2)`

P = 119366.20 Pascal