Question

A race car travels on a circular track at an average rate of 125 mi/h. The radius of the track is 0.320 miles. What is the centripetal acceleration of the car?

Answer 1

The centripetal acceleration is obtained from the quotient of the square of velocity and the radius. Hence, a=
`( v^(2) )/(r)`. Substituting the give, v=125 mi/h and r=0.320 mi, the answer is equal to 48,828.125 mi/
`hr^(2)`.

Answer 2

Answer;

= 48,828.125 mi/hr²

Explanation and solution;

• Centripetal acceleration is the rate of change of angular velocity. Centripetal acceleration occurs towards the center of the circular path along the radius of the circular path.

• Centripetal acceleration is given by; V²/r ;

V = 125 mi/h and r = 0.320 miles

• Thus; centripetal acceleration = 125²/0.320

=15625/0.320

= 48,828.125 mi/hr²