Question

An old-fashioned Chinese restaurant offers a family dinner where you get to choose one dish from “column A” (which has 8 dishes), one dish from “column B” (which has 10 dishes) and one dish from “column C” (which has 5 dishes). How many different family dinners can be chosen?

Answer 1

23 differrent dinners

Answer 2

There are 400 ways to choose the dinner.

Explanation:

Since we have to choose one dish from each column and we have three columns A ,B and C .

Number of choices for Column A = 8

Number of choices for column B = 10

Number of choices for column C = 5 dishes

Number of different family dinners can be chosen = 8x10 x5

= 400 ways

[Using fundamental principle of Multiplication]