Question

How many liters of 1.5 M HCl solution would react completely with 6.5 moles Ca(OH)2?

Answer 1

moles of
`Ca(OH) _(2)` = 6.5 mol
mole ratio of
`Ca(OH) _(2)` : HCl = 1 : 2
∴ since
`Ca(OH) _(2)` cntain 6.5 mol, then HCL contains (2 * 6.5) mol
Thus moles of HCl = 13.0 mol
Volume of HCl needed =
`(moles)/(molar concentration)`
=
`(13.0 mol)/(1.5 mol / dm^(3) )`
= 8.67
`dm^(3)`

`since dm^(3) = L`
then volume of HCL needed = 8.67 L