Question

A gas has an initial volume of 212 cm^3 at a temperature of 293 K and a pressure of 0.98 atm. What is the final pressure of the gas if the volume decreases to 196 cm^3 and the temperature of the gas increases to 308 K?

Answer 1

This can be solved by using one of the different gas laws. This is shown below:

PV / T

Given:
P1 = 0.98 atm
V1 = 212 cm^3
T1 = 293 K

P2 = ?
V2 = 196 cm^3
T2 = 308K

Substituting to the relation:

P1V1/T1 = P2V2/T2

(0.98 * 212)/293 = (P2 * 196)/308
P2 = 1.114 atm