Question

Figure ABCD has vertices A(−3, 2), B(2, 2), C(2, −4), and D(−3, −2). What is the area of figure ABCD?

Answer 1

I believe 25 square units is the right answer.

Answer 2

The area of the figure ABCD is
`25\ units^(2)`

Explanation:

we have

`A(-3, 2), B(2, 2), C(2, -4), D(-3, -2)`

using a graphing tool

Plot the figure

see the attached figure

The figure is a trapezoid

The area of the trapezoid is equal to

`A=(1)/(2)(AD+BC)AB`

Find the distance between the points in the graph

we have

`AD=4\ units`

`BC=6\ units`

`AB=5\ units`

substitute

`A=(1)/(2)(4+6)5=25\ units^(2)`