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What is the factored form of 125x6 – 8?

(5x2 – 2)(25x4 – 10x2 – 4)
(5x2 – 2)(25x4 – 10x2 + 4)
(5x2 – 2)(25x4 + 10x2 + 4)
(5x2 – 2)(25x4 + 10x2 – 4)

User Neshat
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2 Answers

4 votes
Hello,

Answer C

125x^6-8=(5x²)^3-2^3=(5x²-3)((5x²)²+2*5*x²+4)

User DivinusVox
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7 votes

Answer:


(5x^2-2)(25x^4+10x^2+4)

Explanation:

Given expression,


125x^6-8


=(5)^3 (x^2)^3 -2^3
\because (ab)^m=a^mb^m\text{ and }a^(mn)=(a^m)^n


=(5x^2)^3+(-2)^3

By using a³ + b³ = (a-b) (a² -ab + b² )


=(5x^2+(-2)) ((5x^2)^2 - (5x^2* -2) + (-2)^2)


=(5x^2-2)(25x^4+10x^2+4)

Which is the required factor form,

Third option is correct.

User Spoonk
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