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What is the line symmetry for the graph of y= -3x^2+12x-11

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The answer to your question is x=2. what you want to do is find both the x values for your quadratic equation and then add them and divide by 2.
User Michael Chinen
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2 votes

Answer:

The line of symmetry is x=2

Explanation:

Given:
y=-3x^2+12x-11

We are given a quadratic equation and to find the line of symmetry.

As we know the line of symmetry of parabola passes through the x value of vertex.

If vertex of parabola is (h,k) then equation of line of symmetry x=h

So, first we find the vertex of parabola.

For equation:
y=ax^2+bx+c


x=-(b)/(2a)

For given equation, a=-3 and b=12

Therefore,
x=-(12)/(2(-3))


x=2

Hence, The line of symmetry of given parabola is x=2

User Pitchmatt
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