43.1k views
3 votes
The band sold $498 worth of tickets for their spring concert. Adult tickets cost $5 each and student tickets cost $3 each. If they sold 118 tickets, how may adult tickets and how amny students tickets were sold?

a.Write the system of equations which represents this problem.
b. Use substitution to solve.
c. Clearly state the answer to the question

User Ndeuma
by
8.2k points

1 Answer

5 votes
Let: A = adult tickets; S = student tickets

a. 498 = 5A + 3S
118 = A + S

b. S = 118 - A
498 = 5A + 3(118 - A)
498 = 5A + 354 - 3A
498 - 354 = 2A
144 = 2A
A = 72

118 = S + A
118 = 72 + S
118 - 72 = S
S = 46

c. Therefore, there were 72 adult tickets and 46 student tickets sold.

User TheProofIsTrivium
by
8.1k points