Answer:
29.4 g
Step-by-step explanation:
Let's consider the decomposition of potassium chlorate.
KClO₃ → KCl + 1.5 O₂
The molar mass of KClO₃ is 122.55 g/mol. The moles of KClO₃ in 75.0 g are:
75.0 g × (1 mol/ 122.55 g) = 0.612 mol
The molar ratio of KClO₃ to O₂ is 1:1.5. The moles of O₂ are 1.5 × 0.612 mol = 0.918 mol
The molar mass of O₂ is 32.00 g/mol. The mass of O₂ corresponding to 0.918 moles is:
0.918 mol × (32.00 g/mol) = 29.4 g