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If the value of sinx=0.42, what is cos x?
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If the value of sinx=0.42, what is cos x?

User Daniel Santana
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1 Answer

2 votes
from the relation of
sin(x)^2 + cos(x)^2 = 1
(0.42)^2 + cos(x)^2 = 1
cos(x)^2 = 1 - (0.42)^2
cos(x) = √(1-(0.42)^2)
cos(x) = 0.9075
User Calogero
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7.8k points
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