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When solving the equation x2-8x-7=0 by completing the square

User ATechGuy
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x^(2) -8x=7 \\ x^(2) -8x+(-4)^(2) = 7 + (-4)^(2) \\ x^(2) -8x+16 = 7 + 16 \\ (x-4)^(2) =23 \\ x-4= √(23) \\ x-4= \pm 4.8 \\ x= \pm 4.8+4
x = 4.8 + 4 or -4.8 + 4
x = 8.8 or -0.8

User Samuel Pinto
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