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The molar mass of I2 is 253.80 g/mol, and the molar mass of NI3 is 394.71 g/mol. How many moles of I2 will form 3.58 g of NI3?

2 Answers

5 votes

Answer:

Answer is 0.0136.

Step-by-step explanation:

User Michael Merrell
by
9.2k points
3 votes
The balanced chemical reaction is:

N2 +3 I2 = 2NI3

We are given the amount of product formed. This will be the starting point of our calculations.

3.58 g NI3 ( 1 mol NI3 / 394.71 g NI3 ) ( 3 mol I2 / 2 mol NI3 ) = 0.014 mol I2.

Thus, 0.014 mol of I2 is needed to form the given amount of NI3.
User Aditya Pasumarthi
by
7.9k points
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